



We also did that extra sheet but unfortunately I'm not able to post all that. But besides the point here is what I did, pretty sure its correct but might want to make sure monday. I took total current going into the parallel circuit thats part of a series circuit and times it by total resistance of that parallel circuit giving me voltage. Then took that voltage and divided it by each individual resistance to find current of each resistor. Anyhow thats all and I would like to ask to scribe again monday.
Final words: I R SRY :)
No comments:
Post a Comment