Study for the exam carefully. Watch those multiple guess questions-they can be tricky.
Have a great summer & all the best to you in whatever you pursue.
Monday, June 16, 2008
Thursday, June 12, 2008
Wednesday, June 11, 2008
WEDNESDAY JUNE 11, 2008
So, today in class we started off our very productive class by going over the EFFECTS OF CHANGING MAGNETIC FIELDS : INDUCED EMF. If you need to fill in the blanks, feel free to ask anyone for them =).
We also learned about Lenz's Law which basically has to do with electromagnetic induction. We got a sheet to help us figure out how this particular law works. We can use the RHR to help us determine which way the current(s) flow. For example:
Using the RHR, our thumb acts as the "arrow" and our fingers are "rolling upwards" therefore, the currents here are going up.
We also learned about TRANSFORMERS. There are terms that are associated with transformers. These are : STEP-UP TRANSFORMER and STEP-DOWN TRANSFORMER. In a step-up transformer, the primary voltage is less than the secondary voltage, and the current in the primary circuit is greater than the current int he secondary. In a step-down transformer, the primary voltage is greater than the secondary voltage and the cuurent in the primary circuit is less than the current in the secondary circuit.
There is a ratio that goes along with transformers and it looks like this:
We also got a sheet where it is also fill-in-the-blanks and a review sheet which we will go over tomorrow.
PLEASE DO NOT FORGET : TEST ON FRIDAY !!!
[ THE LAST PHYSICS TEST OF THE YEAR LADIES AND GENTLEMEN ]
hello
well im sure the 5th pd class was just as exciting as the 2nd period but man there class is alot more talkative. lol. And how come you talk the 5th pd class on the blog....
Tuesday, June 10, 2008
tuesdays post
So its me again, today in class we looked over a new worksheet and learned a few new equations. Then went on to do 37-1 but not going to show you those answers as the teacher had it done in class. But I will do the 7 questions on electromagnetic induction in a quick fast way.
well that is again if you want anymore detail let me know any I will see what I can do. I need to do at least one more so if no-one else calls tomorrow I would like to do it again. Thanks :)
mondays late post
For Monday all that I can remember is that we reviewed the 2 test given back :) I did pretty good so I was happy. Unfortunately all the answers are written out so theres no real work to be
done but did add a comment or 2. :)
If anyone has any questions concerning the answers let me know and I will try to go through it in more detail.
Monday, June 9, 2008
Sunday, June 8, 2008
fridays post
Hey sorry for scribing late but this was the first time I was able to this weekend. All we did in class was the practise sheet ,Compound circuits, and we all teamed up in did an extra sheet, power in electric circuits, on the whiteboards. So here's the work.
We also did that extra sheet but unfortunately I'm not able to post all that. But besides the point here is what I did, pretty sure its correct but might want to make sure monday. I took total current going into the parallel circuit thats part of a series circuit and times it by total resistance of that parallel circuit giving me voltage. Then took that voltage and divided it by each individual resistance to find current of each resistor. Anyhow thats all and I would like to ask to scribe again monday.
Final words: I R SRY :)
We also did that extra sheet but unfortunately I'm not able to post all that. But besides the point here is what I did, pretty sure its correct but might want to make sure monday. I took total current going into the parallel circuit thats part of a series circuit and times it by total resistance of that parallel circuit giving me voltage. Then took that voltage and divided it by each individual resistance to find current of each resistor. Anyhow thats all and I would like to ask to scribe again monday.
Final words: I R SRY :)
Friday, June 6, 2008
Thursday, June 5, 2008
THURSDAY JUNE 5, 2008 !
So today in class we did a few things .. THE END just kidding :)
The first thing we did was the last couple of pages for CHAPTER 35 ELECTTRIC CIRCUITS. I'm too shy to tell help you fill in the blanks, so let's move on. The next thing we did was go over SIMPLE CIRCUITS on the white boards. There's alot ot things going on, so if you need the answers ask anyone that was present =).
Here's a little bit of cheat sheet if you are ever doubtful of what belongs to which and who belongs to what and so on so forth.
The first thing we did was the last couple of pages for CHAPTER 35 ELECTTRIC CIRCUITS. I'm too shy to tell help you fill in the blanks, so let's move on. The next thing we did was go over SIMPLE CIRCUITS on the white boards. There's alot ot things going on, so if you need the answers ask anyone that was present =).
Here's a little bit of cheat sheet if you are ever doubtful of what belongs to which and who belongs to what and so on so forth.
We also got 2 sheets that deal with COMPOUND CIRCUITS. There are 5 steps to allow us to answer these problems, and they are stated on the first sheet.
PS - I'm not actually shy, I just think you can ask your fellow classmates for the fill-in-the-blanks =)
Wednesday, June 4, 2008
Wednesday, June 4
ANSWERS!!
Grade 12 Electric Circuits: Resistivity Problems
1) A = ρL/R
= (1.7 x 10-8)(20) / (0.10)
= 3.4 x 10-6 m2
A = πr2
r = √(A/π)
= √(3.4 x 10-6 / π) x 2
d = 2.1 x 10-3 m
2) L = RA/ρ
= (1.5)(2.5 x 10-7) / (100 x 10-8)
= 0.38 m
3) ρ = RA/L
= (0.04)(2.0 x 10-6 / (5.0)
= 1.6 x 10-8 Ωm
4) L = RA/ρ
= (3.0)(1.5 x 10-6) / (100 x 10-8)
= 4.5 m
5) A = ρL/R
= (5.5 x 10-8)(0.2) / (0.10)
= 1.1 x 10-7 m2
A = πr2
r = √(A/π)
= √(1.1 x 10-7 m2 / π) x 2
d = 3.7 x 10-4 m
Today we corrected Chapter 23: Study Guide Simple Circuits. We were handed Chapter 34: Electric Current (the “fun” thing) and corrected the first page. Lastly, we were given worksheets called Series and Parallel Circuits, and Simple Circuits.
Grade 12 Electric Circuits: Resistivity Problems
1) A = ρL/R
= (1.7 x 10-8)(20) / (0.10)
= 3.4 x 10-6 m2
A = πr2
r = √(A/π)
= √(3.4 x 10-6 / π) x 2
d = 2.1 x 10-3 m
2) L = RA/ρ
= (1.5)(2.5 x 10-7) / (100 x 10-8)
= 0.38 m
3) ρ = RA/L
= (0.04)(2.0 x 10-6 / (5.0)
= 1.6 x 10-8 Ωm
4) L = RA/ρ
= (3.0)(1.5 x 10-6) / (100 x 10-8)
= 4.5 m
5) A = ρL/R
= (5.5 x 10-8)(0.2) / (0.10)
= 1.1 x 10-7 m2
A = πr2
r = √(A/π)
= √(1.1 x 10-7 m2 / π) x 2
d = 3.7 x 10-4 m
Today we corrected Chapter 23: Study Guide Simple Circuits. We were handed Chapter 34: Electric Current (the “fun” thing) and corrected the first page. Lastly, we were given worksheets called Series and Parallel Circuits, and Simple Circuits.
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